document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=946859>Question 946859</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of one angle is 47' less than the measure of its supplement. Find the measure of each angle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #577632 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=577632\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The measure of one angle is 47' less than the measure of its supplement. Find the measure of each angle.<BR>\n" );
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document.write( "I'm going to assume you meant 47 degrees, not 47 minutes.<BR>\n" );
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document.write( "angle:: x<BR>\n" );
document.write( "supplement:: 180-x<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "180-x = x-47<BR>\n" );
document.write( "2x = 227<BR>\n" );
document.write( "x = 113.5 degrees<BR>\n" );
document.write( "180-x = 66.5 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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