document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=946858>Question 946858</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+37%2F%283z%2B6%29%3C=+1%2F3-+2z%2F%28z%2B2%29+ ALIGN=MIDDLE  ALT=\"+37%2F%283z%2B6%29%3C=+1%2F3-+2z%2F%28z%2B2%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "I am having trouble with multiplying the inequality by the LCD (least common denominator), which is 3z+6. I wrote out the inequality like this:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%283z%2B6%29%2A%2837%2F%283z%2B6%29%29%3C=+%283z%2B6%29%2A%281%2F3%29-%283z%2B6%29%2A+%282z%2F%28z%2B2%29%29+ ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "The problem is I am not sure how to divide the denominators of the fractions into the least common denominator (3z+6). When I try to divide it, it turns into this:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+37+%3C=+3z%2B2-4z-6z+ ALIGN=MIDDLE  ALT=\"+37+%3C=+3z%2B2-4z-6z+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "The inequality above gives me an answer of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+z+%3C=+-5+ ALIGN=MIDDLE  ALT=\"+z+%3C=+-5+\"   DISABLED_style= \"max-width:90%; height:auto;\" > but that is incorrect, so I'm confused. If you are able, could you please explain what I'm doing wrong?    </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #577631 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=577631\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 37/(3z+6)<= 1/3- 2z/(z+2) <BR>\n" );
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document.write( "The LCD is 3(z+2)<BR>\n" );
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document.write( "Multiplying thru by the LCD you get:<BR>\n" );
document.write( "37 <= (z+2) - 6z<BR>\n" );
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document.write( "37 <= -5z + 2<BR>\n" );
document.write( "---<BR>\n" );
document.write( "5z <= 2-37<BR>\n" );
document.write( "5z <= -35<BR>\n" );
document.write( "z <= -7<BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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