document.write( "Question 80458This question is from textbook
\n" ); document.write( ": Solve the equation: 1n x = 1n 2 + 1n (3x - 1)
\n" ); document.write( "I know the answer is 2/5 from the answers in the back of the book.
\n" ); document.write( "I need to know how the solution was solved. \r
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Algebra.Com's Answer #57763 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Given:
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\n" ); document.write( "1n \"x\" = 1n \"2\" + 1n \"%283x+-+1%29\"
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\n" ); document.write( "Collect the logarithms that contain x on one side of the equation. You can do that by
\n" ); document.write( "subtracting ln \"%283x+-+1%29\" from both sides of the equation. When you do that subtraction
\n" ); document.write( "you get:
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\n" ); document.write( "ln \"x\" - ln \"%283x+-+1%29\" = ln \"2\"
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\n" ); document.write( "Now apply the rule that the difference in two logarithms is the same as the log of their division.
\n" ); document.write( "In equation form that rule says:
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\n" ); document.write( "ln \"a\" - ln \"b\" = ln \"%28a%2Fb%29\"
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\n" ); document.write( "With that rule the equation becomes:
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\n" ); document.write( "ln \"x%2F%283x+-+1%29\" = ln \"2\"
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\n" ); document.write( "Look at this carefully ... comparing the left side to the right side. For this to be
\n" ); document.write( "true the two logarithms must be equal, and this means that:
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\n" ); document.write( "\"x%2F%283x+-+1%29+=+2\"
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\n" ); document.write( "To get rid of the denominator, multiply both sides by the denominator of \"3x-1\" to
\n" ); document.write( "get:
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\n" ); document.write( "\"%283x-1%29%2A%28x%2F%283x-1%29%29+=+2%2A%283x+-+1%29\"
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\n" ); document.write( "On the left side the multiplier cancels with the denominator. And multiplying the right
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\n" ); document.write( "\"cross%283x-1%29%2A%28x%2Fcross%283x-1%29%29+=+6x+-+2\"
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\n" ); document.write( "and it reduces to:
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\n" ); document.write( "\"x+=+6x+-+2\"
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\n" ); document.write( "Solve this as you would any equation. You need to gather all the terms that contain x
\n" ); document.write( "on one side of the equation and everything else on the other side. You can do this by
\n" ); document.write( "subtracting 6x from both sides to get:
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\n" ); document.write( "\"+x+-+6x+=+-2\"
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\n" ); document.write( "combine the terms on the left side and the result is:
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\n" ); document.write( "\"-5x+=+-2\"
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\n" ); document.write( "solve for x by dividing both sides by -5 and the outcome is:
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\n" ); document.write( "\"x+=+-2%2F-5+=+2%2F5\"
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\n" ); document.write( "and that's how to get the book answer. Hope this helps to familiarize you with logarithms.
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