document.write( "Question 946751: the width of a rectangle is 40 cm less than its perimeter. The rectangle's are is 102 square cm. find the dementions \n" ); document.write( "
Algebra.Com's Answer #577575 by josgarithmetic(39628)\"\" \"About 
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ASSIGN VARIABLES
\n" ); document.write( "w, width of rectangle
\n" ); document.write( "L, length of rectangle
\n" ); document.write( "p, perimeter of rectangle
\n" ); document.write( "A, area of rectangle
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\n" ); document.write( "A=102
\n" ); document.write( "w=p-40
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\n" ); document.write( "UNKNOWNS: w and L.\r
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\n" ); document.write( "\n" ); document.write( "\"system%28w=p-40%2C2w%2B2L=p%2CwL=A%29\"\r
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\n" ); document.write( "\n" ); document.write( "Note that although p is unknown, it can be eliminated using the w equation
\n" ); document.write( "and the p equation.\r
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\n" ); document.write( "\n" ); document.write( "\"w=p-40\"
\n" ); document.write( "\"w%2B40=p\"
\n" ); document.write( "-
\n" ); document.write( "Equate the two expressions for p;
\n" ); document.write( "\"w%2B40=2w%2B2L\"
\n" ); document.write( "Simplify
\n" ); document.write( "\"40=w%2B2L\"
\n" ); document.write( "\"w%2B2L=40\"\r
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\n" ); document.write( "\n" ); document.write( "The simpler equivalent system without p is
\n" ); document.write( "\"system%28w%2B2L=40%2CwL=A%29\"\r
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\n" ); document.write( "\n" ); document.write( "Substitute for w in the area A equation:
\n" ); document.write( "\"%2840-2L%29L=A\"
\n" ); document.write( "simplify
\n" ); document.write( "\"40L-2L%5E2-A=0\"
\n" ); document.write( "\"-40L%2B2L%5E2%2BA=0\"
\n" ); document.write( "\"highlight_green%282L%5E2-40L%2BA=0%29\"\r
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\n" ); document.write( "\n" ); document.write( "Substituting the given value now for A would be convenient.
\n" ); document.write( "\"2L%5E2-40L%2B102=0\"
\n" ); document.write( "\"L%5E2-20L%2B51=0\"
\n" ); document.write( "FACTORABLE.
\n" ); document.write( "\"%28L-3%29%28L-17%29=0\"
\n" ); document.write( "-
\n" ); document.write( "EITHER \"highlight%28L=3%29\" OR \"highlight%28L=17%29\".\r
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\n" ); document.write( "\n" ); document.write( "Find width, w, using the earlier found formula from the process,
\n" ); document.write( "w=40-2L:
\n" ); document.write( "EITHER \"highlight%28w=34%29\" OR \"highlight%28w=6%29\"\r
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\n" ); document.write( "\n" ); document.write( "SUMMARY OF SOLUTIONS
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\n" ); document.write( "The dimensions are either 3 & 34, or 17 & 6.
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