document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=946704>Question 946704</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The difference between two numbers is 8 and twice the sum of their reciprocals are equal to 3 times the difference of their reciprocals. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #577552 by </B><A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><B>amarjeeth123(570)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=577552\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let one number be x.<BR>\n" );
document.write( "Then the other number is (x+8).<BR>\n" );
document.write( "Twice the sum of their reciprocals are equal to 3 times the difference of their reciprocals.<BR>\n" );
document.write( "2(1/x+1/(x+8))=3(1/x-1/(x+8))<BR>\n" );
document.write( "Simplifying we get<BR>\n" );
document.write( "2((x+8)+x)=3((x+8)-x)<BR>\n" );
document.write( "2(2x+8)=24<BR>\n" );
document.write( "4(x+4)=24<BR>\n" );
document.write( "x+4=6<BR>\n" );
document.write( "x=2<BR>\n" );
document.write( "The numbers are 2 and 10. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );