document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=946622>Question 946622</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The point (-3/5, y) in the third quadrant corresponds to angle &#952; on the unit circle.\r<BR>\n" );
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document.write( "The value of sec &#952; is ? , and the value of cot &#952; is ? <BR>\n" );
document.write( "so what are the values of sec&#952; and cot&#952;?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #577547 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=577547\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The point (-3/5, y) in the third quadrant corresponds to angle &#952; on the unit circle.<BR>\n" );
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document.write( "r = sqrt[y^2-(3/5)^2] = sqrt[(25y^2-9)/25]<BR>\n" );
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document.write( " The value of sec &#952; is ?<BR>\n" );
document.write( "sec(t) = x/r = (-3/5)/sqrt[(25y^2-9)/25]<BR>\n" );
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document.write( "the value of cot &#952; is ?<BR>\n" );
document.write( "cot(t) = x/y = (-3/5)/y = -3/(5y)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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