document.write( "Question 80511: Directions: decide whether the graph of the equation opens up or down. Then find the coordinates of the vertex.as in ... y=3x^2 and/or y=2x^2-4x+3 \n" ); document.write( "
Algebra.Com's Answer #57750 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Directions: decide whether the graph of the equation opens up or down. Then find the coordinates of the vertex.as in ... y=3x^2 and/or y=2x^2-4x+3 \n" ); document.write( "----- \n" ); document.write( "y= 3s^2 opens up. \n" ); document.write( "Since a=3 and b=0 the x-coordinate of the vertex = -b/2a = -0/6=0 \n" ); document.write( "When x=0, y=0 so the vertex is at (0,0) \n" ); document.write( "--------------- \n" ); document.write( "y=2x^2-4x+3 opens up \n" ); document.write( "Since a=2, and b=-4, x=-b/2a = -(-4/4)=1 \n" ); document.write( "When x=1, y=2-4+3=1 so the vertex is at (1,1) \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |