document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=946574>Question 946574</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many gallons of a 50% saltwater solution must be added to 10 gallons of a 15% solution to obtain a 35% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #577483 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=577483\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 10 gallon at 15% + x gallon at 50% = 10+x gallon at 35% We will rewrite:\r<BR>\n" );
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document.write( ".15(10) + .50(x) = .35(10+x)\r<BR>\n" );
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document.write( "1.5 + .50x = 3.5 + .35x Subtract 1.5 from both sides:\r<BR>\n" );
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document.write( ".5x = 2 + .35x now subtract .35x from both sides and you get:\r<BR>\n" );
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document.write( ".15x = 2 Finally divide both sides by .15:\r<BR>\n" );
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document.write( "x = 13.33 gallon of 50% solution. </SPAN>\n" );
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