document.write( "Question 946571: A large pipe takes 24 hours less to fill a tank than a smaller pipe. If both pipes are turned on it takes 16 hours to fill the tank. How many hours will each pipe take to fill the tank by itself?
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Algebra.Com's Answer #577463 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
A large pipe takes 24 hours less to fill a tank than a smaller pipe. If both pipes are turned on it takes 16 hours to fill the tank. How many hours will each pipe take to fill the tank by itself?\r
\n" ); document.write( "\n" ); document.write( "Let x=amount of time it takes small pipe
\n" ); document.write( "Then small pipe fills at the rate of 1/x of the tank per hour
\n" ); document.write( "x-24=amount of time it takes large pipe
\n" ); document.write( "Then large pipe fills at the rate of 1/(x-24) of the tank per hour\r
\n" ); document.write( "\n" ); document.write( "With both pipes turned on, they fill at the rate of 1/16 of the tank per hour\r
\n" ); document.write( "\n" ); document.write( "Sooooo
\n" ); document.write( "(1/x) + 1/(x-24)=1/16 multiply each tem by 16x(x-24)
\n" ); document.write( "16(x-24)+16x=x(x-24)
\n" ); document.write( "16x-384+16x=x^2-24x
\n" ); document.write( "32x-384=x^2-24x
\n" ); document.write( "x^2-56x+384=0 quadratic in standard form and it can be factored
\n" ); document.write( "(x-8)(x-48)=0
\n" ); document.write( "x=8----no good can't have negative hours for large tank
\n" ); document.write( "So
\n" ); document.write( "x=48 hrs---time it takes small pipe
\n" ); document.write( "x-24=48-24=24 hrs time it takes large pipe
\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "(1/48)+(1/24)=???(1/16)
\n" ); document.write( "3/48=1/16
\n" ); document.write( "1/16=1/16\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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