document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=79899>Question 79899</A>: <I><SPAN STYLE=\"word-break: break-all;\"> need help with the addition method<BR>\n" );
document.write( "x-2y= -24  you have to subsitute the numbers in the equation. Thanks!<BR>\n" );
document.write( "-6x-3y=9   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #57746 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=57746\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> multiply the first equation by 6 & we get<BR>\n" );
document.write( "6x-12y=-144 now add thiese 2 equations<BR>\n" );
document.write( "-6x-3y=9<BR>\n" );
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document.write( "-15y=-135<BR>\n" );
document.write( "y=-135/-15<BR>\n" );
document.write( "y=9 answer.<BR>\n" );
document.write( "x-2*9=-24<BR>\n" );
document.write( "x-18=-24<BR>\n" );
document.write( "x=-24+18<BR>\n" );
document.write( "x=-6 answer.<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );