document.write( "Question 80501: help me someone please!!\r
\n" ); document.write( "\n" ); document.write( "The length of a rectangle is 1 cm longer than its width. If the diagonal
\n" ); document.write( "of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle?
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Algebra.Com's Answer #57743 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
X^2+(X+1)^2=4^2 X=WIDTH + (X+1)=LENGTH.
\n" ); document.write( "X^2+X^2+2X+1=16
\n" ); document.write( "2X^2+2X+1-16=0
\n" ); document.write( "2X^2+2X-15=0
\n" ); document.write( "using the quadratic equation we get:
\n" ); document.write( "x=(-2+-sqrt[2^2-4*2*-15])/2*2
\n" ); document.write( "x=(-2+-sqrt[4+120])/4
\n" ); document.write( "x=(-2+-sqrt124)/4
\n" ); document.write( "x=(-2+-11.1355)/4
\n" ); document.write( "x=(-2+11.1355)/4
\n" ); document.write( "x=9.1355/4
\n" ); document.write( "x=2.284 answer.
\n" ); document.write( "x=(-2-11.1355)/4
\n" ); document.write( "x=-13.1355/4
\n" ); document.write( "x=-3.2839 answer.\r
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