document.write( "Question 946485: This question is really throwing me off, I'm not even sure how to start it off..Can someone please help?\r
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document.write( "Assume that each birth to the same parents is an independent event with p(girl)=p(boy)= 1/2. For a family with 3 children, find the probability of exactly 2 boys, given that the first child is a boy. \n" );
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Algebra.Com's Answer #577420 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! Note that independent events are not affected by previous events. \n" ); document.write( "therefore, \n" ); document.write( "Probability of an event happening = Number of ways it can happen / Total number of outcomes \n" ); document.write( "lets look at the total number of outcomes with the first child a boy, \n" ); document.write( "(boy, girl, boy), (boy, boy, girl), (boy, boy, boy), (boy, girl, girl) \n" ); document.write( "now, \n" ); document.write( "the probability of exactly 2 boys, given that the first child is a boy = 2/4 = 1/2 \n" ); document.write( " \n" ); document.write( " |