document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=946486>Question 946486</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 25 workers are needed to build a house in 16 days. how many days will 28 wokers working at the same rate take to build the same house? inverse proportion question solve with unitary method<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #577418 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=577418\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> unitary method involves the inverse variation equation of y = x/k\r<BR>\n" );
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document.write( "16 = number of days = y<BR>\n" );
document.write( "25 = number of workers = x\r<BR>\n" );
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document.write( "equation of y = k/x becomes 16 = k/25.\r<BR>\n" );
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document.write( "solve for k to get k = 16 * 25 = 400\r<BR>\n" );
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document.write( "when you have 28 workers, the equation becomes y = 400 / 28 which simplifies to 100 / 7 days which is the same as 14 and 2/7 days.\r<BR>\n" );
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document.write( "it would take 28 workers 14 and 2/7 days working at the same rate per worker.\r<BR>\n" );
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