document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=946502>Question 946502</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In rectangle PQRS, the ratio of angle PSQ to angle PQS is 1:5. What is the size of angle QSR? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #577409 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=577409\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> both angles become acute angles in a right triangle.\r<BR>\n" );
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document.write( "if angle PSQ is equal to x, then angle PQS is equal to 5x.\r<BR>\n" );
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document.write( "since they are acute angles of a right triangle, their sum has to be equal to 90 degrees.\r<BR>\n" );
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document.write( "you get x + 5x = 90 which becomes 6x = 90 which becomes x = 15.\r<BR>\n" );
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document.write( "PSQ is equal to 15 degrees.<BR>\n" );
document.write( "PQS is equal to 75 degrees.<BR>\n" );
document.write( "their sum is 90<BR>\n" );
document.write( "the ratio of PSQ to PQS is 15 to 75 which reduces to 1 to 5 because 75 / 15 is equal to 5.\r<BR>\n" );
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