document.write( "Question 946484: I've been stuck on this question on my study guide and i really need to understand how to do it \r
\n" ); document.write( "\n" ); document.write( "An urn contains 4 white balls and 3 green balls. A set of 3 balls are drawn from the urn. Find the probability that the third ball is white given that the first two are white.
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Algebra.Com's Answer #577402 by Theo(13342)\"\" \"About 
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\n" ); document.write( "there are 4 white balls out of 7 in the urn to start with.\r
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\n" ); document.write( "\n" ); document.write( "the probability of drawing a white ball on the first draw is therefore 4/7.\r
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\n" ); document.write( "\n" ); document.write( "your first draw is a white ball.\r
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\n" ); document.write( "\n" ); document.write( "there are 3 white balls out of 6 left in the urn after the first draw.\r
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\n" ); document.write( "\n" ); document.write( "the probability of drawing a white ball on the second draw is therefore 3/6.\r
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\n" ); document.write( "\n" ); document.write( "your second draw is a white ball.\r
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\n" ); document.write( "\n" ); document.write( "there are 2 white balls out of 5 left in the urn after the second draw.\r
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\n" ); document.write( "\n" ); document.write( "the probability of drawing a white ball on the third draw is therefore 2/5.\r
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\n" ); document.write( "\n" ); document.write( "given that you drew a white ball on the first 2 draws, the probability of drawing a white ball on the third draw is 2/5 because there are 2 white balls left out of a total of 5 balls left in the urn.\r
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\n" ); document.write( "\n" ); document.write( "that's my understanding.\r
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