document.write( "Question 946472: If you roll two dice what is the probability that sum of numbers on two dice will be 7?
\n" ); document.write( "Tip: P = number of cases with sum 7 over total possible number of cases.
\n" ); document.write( "Keep in mind, 6-1 and 1-6 considered as two different cases.
\n" ); document.write( "The same for 5-2, 2-5 and so on.
\n" ); document.write( "Simplify final fraction. \n" ); document.write( "

Algebra.Com's Answer #577375 by Fombitz(32388) $\"\"$ $\"About$

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Look at all possible outcomes, there are $\"6%5E2=36\"$ of them.
\n" ); document.write( "1-1 1-2 1-3 1-4 1-5 1-6
\n" ); document.write( "2-1 2-2 2-3 2-4 2-5 2-6
\n" ); document.write( "3-1 3-2 3-3 3-4 3-5 3-6
\n" ); document.write( "4-1 4-2 4-3 4-4 4-5 4-6
\n" ); document.write( "5-1 5-2 5-3 5-4 5-5 5-6
\n" ); document.write( "6-1 6-2 6-3 6-4 6-5 6-6
\n" ); document.write( "Of those 36, 6 of them sum to 7.
\n" ); document.write( "1-6 2-5 3-4 4-3 5-2 6-1
\n" ); document.write( "So,
\n" ); document.write( " $\"P=6%2F36=1%2F6\"$
\n" ); document.write( " \n" ); document.write( "

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