document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=946388>Question 946388</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this problem: How many kilograms of 50 percent silver alloy and 10 percent silver alloy must be combined to obtain 24 kilograms of a 25 percent of silver alloy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #577362 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=577362\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many kilograms of 50 percent silver alloy and 10 percent silver alloy must be combined to obtain 24 kilograms of a 25 percent of silver alloy?<BR>\n" );
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document.write( "let x=amt of 50% silver alloy to be combined<BR>\n" );
document.write( "24-x=amy of 10% silver alloy to be combined<BR>\n" );
document.write( "50%x+10%(24-x)=25%*24<BR>\n" );
document.write( ".50x+2.4-.10x=6<BR>\n" );
document.write( ".40x=3.6<BR>\n" );
document.write( "x=9<BR>\n" );
document.write( "24-9=15<BR>\n" );
document.write( "amt of 50% silver alloy to be combined=9 kg<BR>\n" );
document.write( "amy of 10% silver alloy to be combined=15 kg </SPAN>\n" );
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