document.write( "Question 946254: I don't understand how (n-2)/(n^3-8) becomes 1/(n^2+2n+4).\r
\n" ); document.write( "\n" ); document.write( "I get how you take out the common factor of (n-2), but why does the denominator become n^2+2n+4 instead of n^2+4?
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Algebra.Com's Answer #577286 by MathTherapy(10552)\"\" \"About 
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I don't understand how (n-2)/(n^3-8) becomes 1/(n^2+2n+4).\r
\n" ); document.write( "\n" ); document.write( "I get how you take out the common factor of (n-2), but why does the denominator become n^2+2n+4 instead of n^2+4?
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\n" ); document.write( "\"%28n+-+2%29%2F%28n%5E3+-+8%29\"
\n" ); document.write( "\"%28n+-+2%29%2F%28%28n+-+2%29%28n%5E2+%2B+2n+%2B+4%29%29\" ----- Factoring denominator
\n" ); document.write( "\"cross%28%28n+-+2%29%29%2F%28cross%28%28n+-+2%29%29%28n%5E2+%2B+2n+%2B+4%29%29\" ---- Cancelling n - 2 in numerator and denominator
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