document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=946254>Question 946254</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I don't understand how (n-2)/(n^3-8) becomes 1/(n^2+2n+4).\r<BR>\n" );
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document.write( "I get how you take out the common factor of (n-2), but why does the denominator become n^2+2n+4 instead of n^2+4? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #577282 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=577282\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I don't understand how (n-2)/(n^3-8) becomes 1/(n^2+2n+4).\r<BR>\n" );
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document.write( "I get how you take out the common factor of (n-2), but why does the denominator become n^2+2n+4 instead of n^2+4?<BR>\n" );
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document.write( "(n-2)*(n^2+4) = n^3 - 2n^2 + 4n - 8<BR>\n" );
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document.write( "That's <> n^ - 8<BR>\n" );
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