document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=80431>Question 80431</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would you solve the following equation?\r<BR>\n" );
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document.write( "3x-5(3x-7) = 2(x+9)+45\r<BR>\n" );
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document.write( "Thank you for your help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #57726 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=57726\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x-5(3x-7) = 2(x+9)+45 [use the order of operations to simplify (PEMDAS)]<BR>\n" );
document.write( "3x-15x+35=2x+18+45 [use the distributive property to multiply]<BR>\n" );
document.write( "-12x+35=2x+63 [combine like-terms]<BR>\n" );
document.write( "-12x+35-35=2x+63-35 [isolate the x=term]<BR>\n" );
document.write( "-12x=2x+28<BR>\n" );
document.write( "-12x-2x=2x-2x+28<BR>\n" );
document.write( "-14x=28<BR>\n" );
document.write( "-14x/-14=28/-14<BR>\n" );
document.write( "x=-2<BR>\n" );
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document.write( "check by plugging (x=-2) back into the original equation and solve<BR>\n" );
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