document.write( "Question 946224: Hello! I was asked this question: \"The general equation of a plane is Ax + By + Cz = D, where A, B, C, and D are real numbers and A is nonnegative. Find the equation of the plane containing the points (3, 0, 0), (0, 6, 0), and (0, 0, 6). Show each step of your process.\" I am not quite sure on how to complete this question. If you could walk me through this, that would be great. Thanks \n" ); document.write( "

Algebra.Com's Answer #577252 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let P=(3,0,0), Q=(0,6,0), and R=(0,0,6).
\n" ); document.write( "Find PQ and PR, two vectors that lie in the plane.
\n" ); document.write( "PQ=(-3,6,0)
\n" ); document.write( "PR=(-3,0,6)
\n" ); document.write( "Now find the cross product to have a vector normal to the plane.
\n" ); document.write( "PQ X PR= (36,18,18)=(2,1,1)
\n" ); document.write( "So the plane has the form,
\n" ); document.write( " $\"2x%2By%2Bz=D\"$
\n" ); document.write( "Now use any point to solve for D.
\n" ); document.write( " $\"2%283%29%2B0%2B0=D\"$
\n" ); document.write( " $\"D=6%7D%7D%5D%0D%0A.%0D%0A.%0D%0A%7B%7B%7B2x%2By%2Bz=6\"$ \r
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