document.write( "Question 946175: An object is projected vertically from the top of a building with an initial velocity of 128ft/sec. It's distance is s(t) in feet above the ground after t seconds is given by the equation.\r
\n" ); document.write( "\n" ); document.write( "S(t)= -16t^2 + 128t +80\r
\n" ); document.write( "\n" ); document.write( "a. Find its maximum distance above the ground.\r
\n" ); document.write( "\n" ); document.write( "b. Find the height of the building.\r
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Algebra.Com's Answer #577223 by Alan3354(69443)\"\" \"About 
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An object is projected vertically from the top of a building with an initial velocity of 128ft/sec. It's [sic] distance is s(t) in feet above the ground after t seconds is given by the equation.\r
\n" ); document.write( "\n" ); document.write( "S(t)= -16t^2 + 128t +80\r
\n" ); document.write( "\n" ); document.write( "a. Find its maximum distance above the ground.
\n" ); document.write( "Max height is the vertex of the parabola at t - -b/2a
\n" ); document.write( "t = -128/-32 = 4 seconds
\n" ); document.write( "s(4) = -16*16 + 128*4 + 80 = 336 feet
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\n" ); document.write( "b. Find the height of the building.
\n" ); document.write( "It's s(0) = 80 feet
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