document.write( "Question 946121: a woman is now 4 times older than her daughter. Six years ago the product of their age was 136. whats their present age \n" ); document.write( "

Algebra.Com's Answer #577186 by Fombitz(32388) $\"\"$ $\"About$

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$\"W=4D\"$
\n" ); document.write( "Six years ago,
\n" ); document.write( " $\"%28W-6%29%28D-6%29=136\"$
\n" ); document.write( "Substituting,
\n" ); document.write( " $\"%284D-6%29%28D-6%29=136\"$
\n" ); document.write( " $\"4D%5E2-30D%2B36=136\"$
\n" ); document.write( " $\"4D%5E2-30D-100=0\"$
\n" ); document.write( " $\"2D%5E2-15D-50=0\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"%28D-10%29%282D%2B5%29=0\"$
\n" ); document.write( "Only the positive solution makes sense.
\n" ); document.write( " $\"D-10=0\"$
\n" ); document.write( " $\"D=10\"$
\n" ); document.write( "So then,
\n" ); document.write( " $\"W=4%2810%29\"$
\n" ); document.write( " $\"W=40\"$
\n" ); document.write( " \n" ); document.write( "

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