document.write( "Question 946049: The length of each side of a square in 3 inches more than the length of each side of a smaller square. The sum of the areas is 425 inches squared. Find the length of the sides of both triangles. \n" ); document.write( "

Algebra.Com's Answer #577156 by Fombitz(32388) $\"\"$ $\"About$

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Do you mean length of the sides of both squares?
\n" ); document.write( "I hope so.
\n" ); document.write( "Let $\"s\"$ be the side of the larger square.
\n" ); document.write( " $\"s%5E2%2B%28s-3%29%5E2=425\"$
\n" ); document.write( " $\"s%5E2%2Bs%5E2-6s%2B9=425\"$
\n" ); document.write( " $\"2s%5E2-6s-416=0\"$
\n" ); document.write( " $\"s%5E2-3s-208=0\"$
\n" ); document.write( " $\"%28s-16%29%28s%2B13%29=0\"$
\n" ); document.write( "We only need the positive solution.
\n" ); document.write( " $\"s-16=0\"$
\n" ); document.write( " $\"s=16\"$
\n" ); document.write( "So then,
\n" ); document.write( " $\"s-3=13\"$
\n" ); document.write( "First square has length 16, smaller square has length 13.
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