document.write( "Question 946034: sin(x/2) + cos(x) = 0
\n" ); document.write( "Give all answers
\n" ); document.write( " From 0 to 2pi
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #577132 by lwsshak3(11628) $\"\"$ $\"About$

You can put this solution on YOUR website!
sin(x/2) + cos(x) = 0
\n" ); document.write( "Give all answers
\n" ); document.write( "From 0 to 2pi
\n" ); document.write( "***
\n" ); document.write( " $\"sin%28x%2F2%29%2Bcosx=0\"$
\n" ); document.write( " $\"sqrt%28%281-cosx%29%2F2%29%2Bcosx=0\"$
\n" ); document.write( " $\"sqrt%28%281-cosx%29%2F2%29=-cosx\"$
\n" ); document.write( "square both sides:
\n" ); document.write( "(1-cosx)/2=cos^2(x)
\n" ); document.write( "1-cosx=2cos^2(x)
\n" ); document.write( "2cos2(x)+cosx-1=0
\n" ); document.write( "(2cosx-1)(cosx+1)=0
\n" ); document.write( "..
\n" ); document.write( "2cosx-1=0
\n" ); document.write( "cosx=1/2
\n" ); document.write( "x=π/3,5π/3
\n" ); document.write( "or
\n" ); document.write( "cosx+1=0
\n" ); document.write( "cosx=-1
\n" ); document.write( "x=π \n" ); document.write( "

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