document.write( "Question 945992: twenty kilograms of nuts consisting of cashews worth $6.00 per kg, pecans worth $2.50 per kg, and peanuts worth $1.50 per kg are mixed. there are twice as many pecans as cashews, and there are as many kilograms of peanuts as pecans. the total value of nuts is $56. how many of each are there? must be solved algebraically using the 5 steps. \n" ); document.write( "
Algebra.Com's Answer #577068 by stanbon(75887)\"\" \"About 
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twenty kilograms of nuts consisting of cashews worth $6.00 per kg, pecans worth $2.50 per kg, and peanuts worth $1.50 per kg are mixed. there are twice as many pecans as cashews, and there are as many kilograms of peanuts as pecans. the total value of nuts is $56. how many of each are there? must be solved algebraically using the 5 steps.
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\n" ); document.write( "Equations:
\n" ); document.write( "h + c + p = 20 kg
\n" ); document.write( "6h+2.5c+1.5p = 56 dollars
\n" ); document.write( "p = c
\n" ); document.write( "------
\n" ); document.write( "Modify::
\n" ); document.write( "Substitute c for \"p\" to get:
\n" ); document.write( "h + 2c = 20
\n" ); document.write( "6h + 4c = 56
\n" ); document.write( "=======
\n" ); document.write( "Modify::
\n" ); document.write( "h + 2c = 20
\n" ); document.write( "3h + 2c = 28
\n" ); document.write( "---------
\n" ); document.write( "Subtract::
\n" ); document.write( "2h = 8
\n" ); document.write( "h = 4 kg (amt. of cashews needed)
\n" ); document.write( "-----
\n" ); document.write( "4+ 2c = 20
\n" ); document.write( "2c = 16
\n" ); document.write( "c = 8 kg (amt. of picans needed)
\n" ); document.write( "----------
\n" ); document.write( "Solve for \"p\"::
\n" ); document.write( "h + c + p = 20 kg
\n" ); document.write( "4 + 8 + p = 20
\n" ); document.write( "p = 8 kg (amt. of peanuts needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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