document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=945931>Question 945931</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please explain why the domain of f(x)=(x-2)^2 is all real numbers? my calculations were\r<BR>\n" );
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document.write( "f(x)=(x-2)^2<BR>\n" );
document.write( "(x-2)(x-2)<BR>\n" );
document.write( "x=2 therefore the domin cannot be postive 2 so (-&#8734;,2)U(2,&#8734;) wouldn't this exclude the 2's and therefore it wouldn't be all real numbers?\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #577041 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=577041\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Can you please explain why the domain of f(x)=(x-2)^2 is all real numbers? my calculations were\r<BR>\n" );
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document.write( "f(x)=(x-2)^2<BR>\n" );
document.write( "(x-2)(x-2)<BR>\n" );
document.write( "x=2 therefore the domin cannot be postive 2 so (-&#8734;,2)U(2,&#8734;) wouldn't this exclude the 2's and therefore it wouldn't be all real numbers?<BR>\n" );
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document.write( "x = +2 --> f(x) = 0<BR>\n" );
document.write( "No reason to exclude it.<BR>\n" );
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