document.write( "Question 945891: A 600 mile trip from one city to another takes 4 hours when the plane is flying with the wind. The return trip against the wind takes 5 hours. Find the rate of the plane in still air and the rate of the wind. \n" ); document.write( "
Algebra.Com's Answer #576995 by TimothyLamb(4379)\"\" \"About 
You can put this solution on YOUR website!
x = speed of airplane in still air (mph)
\n" ); document.write( "y = speed of the wind (mph)
\n" ); document.write( "---
\n" ); document.write( "s = d/t
\n" ); document.write( "---
\n" ); document.write( "downwind:
\n" ); document.write( "x + y = 600/4
\n" ); document.write( "x + y = 150
\n" ); document.write( "---
\n" ); document.write( "upwind:
\n" ); document.write( "x - y = 600/5
\n" ); document.write( "x - y = 120
\n" ); document.write( "---
\n" ); document.write( "put the system of linear equations into standard form
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\n" ); document.write( "x + y = 150
\n" ); document.write( "x - y = 120
\n" ); document.write( "---
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\n" ); document.write( "---
\n" ); document.write( "solution:
\n" ); document.write( "x = 135
\n" ); document.write( "y = 15
\n" ); document.write( "---
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