document.write( "Question 80419: Solve for x\r
\n" ); document.write( "\n" ); document.write( "(1/7)^x=49
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Algebra.Com's Answer #57697 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve for x:
\n" ); document.write( "\"%281%2F7%29%5Ex+=+49\" But \"49+=+7%5E2\" = \"1%2F7%5E%28-2%29+=+%281%2F7%29%5E-2\", so we get:
\n" ); document.write( "\"%281%2F7%29%5Ex+=+%281%2F7%29%5E-2\", therefore x = -2\r
\n" ); document.write( "\n" ); document.write( "If you are not comfortable with this approach, here's another one:
\n" ); document.write( "\"%281%2F7%29%5Ex+=+49\" Take the logarithm of both sides.
\n" ); document.write( "\"Log%5B10%5D%281%2F7%29%5Ex+=+Log%5B10%5D%2849%29\" Apply the power rule to the left side.
\n" ); document.write( "\"x%2ALog%5B10%5D%281%2F7%29+=+Log%5B10%5D%2849%29\" Divide both sides by \"Log%5B10%5D%281%2F7%29\"
\n" ); document.write( "\"x+=+%28Log%5B10%5D%2849%29%29%2FLog%5B10%5D%281%2F7%29\" Do this with your calculator.
\n" ); document.write( "\"x+=+-2\"
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