document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=945791>Question 945791</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello,<BR>\n" );
document.write( "I have a bit more information on my barrel question. 228lts approx 60gal.<BR>\n" );
document.write( "Barrel Height = 89cm  Thickness of the barrel is 25mm<BR>\n" );
document.write( "Belly Dia.  = 71cm Circ.= 223cm<BR>\n" );
document.write( "Top & Bottom Dia. = 58cm Circ. = 182cm<BR>\n" );
document.write( "Question 1- What is the internal surface area?<BR>\n" );
document.write( "Question 2- What is the surface area of liquid in contact with the surface of the inside of the barrel? <BR>\n" );
document.write( "I need to be able to work out the equivalent area for a 1lt jar with a piece of wood in it to have the same ratio as the liquid in the barrel.<BR>\n" );
document.write( "I hope there is enough information this time.\r<BR>\n" );
document.write( "\n" );
document.write( "Many thanks.\r<BR>\n" );
document.write( "\n" );
document.write( "Ian.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #576949 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=576949\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I have a bit more information on my barrel question. 228lts approx 60gal.<BR>\n" );
document.write( "Barrel Height = 89cm  Thickness of the barrel is 25mm<BR>\n" );
document.write( "Belly Dia.  = 71cm Circ.= 223cm<BR>\n" );
document.write( "Top & Bottom Dia. = 58cm Circ. = 182cm<BR>\n" );
document.write( "Question 1- What is the internal surface area?<BR>\n" );
document.write( "----<BR>\n" );
document.write( "The belly diameter is only 13 cm more than the top and bottom, so using the average for the diameter will cause a small difference.<BR>\n" );
document.write( "(58 + 71)/2 = 64.5 cm avg diameter<BR>\n" );
document.write( "--> Outside dimensions: r = 32.25 cm<BR>\n" );
document.write( "h = 89 cm<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Inside dimensions: r = 32 cm, h = 88.5 cm<BR>\n" );
document.write( "Inside SA = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2Ar%5E2+%2B+pi%2Ar%5E2+%2B+2pi%2Ar%2Ah ALIGN=MIDDLE  ALT=\"pi%2Ar%5E2+%2B+pi%2Ar%5E2+%2B+2pi%2Ar%2Ah\"   DISABLED_style= \"max-width:90%; height:auto;\" > (bottom, top & sides)<BR>\n" );
document.write( "= <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2Api%2A1024+%2B+2%2Api%2A32%2A88.5+=+pi%2A%282048+%2B+5664%29+=+7712%2Api ALIGN=MIDDLE  ALT=\"2%2Api%2A1024+%2B+2%2Api%2A32%2A88.5+=+pi%2A%282048+%2B+5664%29+=+7712%2Api\"   DISABLED_style= \"max-width:90%; height:auto;\" > sq cm<BR>\n" );
document.write( "=~ 24228 sq cm<BR>\n" );
document.write( "==========================\r<BR>\n" );
document.write( "\n" );
document.write( "Question 2- What is the surface area of liquid in contact with the surface of the inside of the barrel?<BR>\n" );
document.write( "If it's full, it's the same as above, 24228 sq cm.<BR>\n" );
document.write( "===========================\r<BR>\n" );
document.write( "\n" );
document.write( "I need to be able to work out the equivalent area for a 1lt jar with a piece of wood in it to have the same ratio as the liquid in the barrel.<BR>\n" );
document.write( "====================<BR>\n" );
document.write( "24228 sq cm/228 liters --> 106 sq cm per liter </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );