document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=945786>Question 945786</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if 3 is subtracted from a number and the remainder is multiplied by 13 the product becomes 91 find the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #576936 by </B><A HREF=/tutors/aboutme.mpl?userid=dileepkumarabhijith><B>dileepkumarabhijith(12)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dileepkumarabhijith><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=576936\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> hi\r<BR>\n" );
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document.write( "let the number be x\r<BR>\n" );
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document.write( "according to the question remainder is (x-3).\r<BR>\n" );
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document.write( "(x-3)is then multiplied by 13<BR>\n" );
document.write( "that is,\r<BR>\n" );
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document.write( "(x-3)*13\r<BR>\n" );
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document.write( "(x-3)*13=91     13x-39=91 \r<BR>\n" );
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document.write( "13x=130\r<BR>\n" );
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document.write( "x=130/13=10\r<BR>\n" );
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document.write( "therefore the required number is 10\r<BR>\n" );
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document.write( " </SPAN>\n" );
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