document.write( "Question 945773: Log2^x+log4^x+log8^x=21/4, find x \n" ); document.write( "

Algebra.Com's Answer #576928 by lwsshak3(11628) $\"\"$ $\"About$

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Log2^x+log4^x+log8^x=21/4, find x
\n" ); document.write( " $\"log%28%282%5Ex%2A4%5Ex%2A8%5Ex%29%29=21%2F4\"$
\n" ); document.write( " $\"log%28%282%5E%28x%29%2A2%5E%282x%29%2A2%5E%283x%29%29%29=21%2F4\"$
\n" ); document.write( " $\"log%28%282%5E%286x%29%29%29=21%2F4\"$
\n" ); document.write( " $\"6xlog%282%29=21%2F4\"$
\n" ); document.write( "6x=21/4log2
\n" ); document.write( "x=21/(24log2)
\n" ); document.write( "x≈2.9067 \n" ); document.write( "

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