document.write( "Question 945694: The town swimming pool is d feet deep. The width of the pool is 10 feet greater than 5 times the depth. The length of the pool is 25 feet greater than the width.
\n" ); document.write( "A.Write and simplify an expression to represent the volume of the pool.
\n" ); document.write( "B. If the pool holds 51,000 ft3 of water, what are the dimensions of the pool?
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Algebra.Com's Answer #576910 by ankor@dixie-net.com(22740)\"\" \"About 
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The town swimming pool is d feet deep.
\n" ); document.write( " The width of the pool is 10 feet greater than 5 times the depth.
\n" ); document.write( "w = 5d+10
\n" ); document.write( " The length of the pool is 25 feet greater than the width.
\n" ); document.write( "L = w + 25
\n" ); document.write( "Replace w with (5d+10)
\n" ); document.write( "L = (5d+10) + 25
\n" ); document.write( "L = 5d + 35
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\n" ); document.write( "A.Write and simplify an expression to represent the volume of the pool.
\n" ); document.write( "Volume = L*w*d
\n" ); document.write( "replace L and w
\n" ); document.write( "V = (5d+35)*(5d+10)* d
\n" ); document.write( "V = (25d^2 + 50d + 175d + 350)* d
\n" ); document.write( "V = (25d^2 + 225d + 350)*d
\n" ); document.write( "Factor out 25 and you have
\n" ); document.write( "V = 25d(d^2 + 9d + 14)
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\n" ); document.write( "B. If the pool holds 51,000 ft3 of water, what are the dimensions of the pool?
\n" ); document.write( "25d(d^2 + 9d + 14) = 51000
\n" ); document.write( "divide both sides by 25
\n" ); document.write( "d(d^2 + 9d + 14) = 2040
\n" ); document.write( "the equation
\n" ); document.write( "d^3 + 9d^2 + 14d - 2040 = 0
\n" ); document.write( "Using the Ti83, I got d = 10 ft is the depth
\n" ); document.write( "then
\n" ); document.write( "5(10) + 10 = 60 ft is the width
\n" ); document.write( "and
\n" ); document.write( "5(10) + 35 = 85 ft is length
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\n" ); document.write( "Check this, find the vol using these values; 85 * 60 * 10 = 51000
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