document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=945676>Question 945676</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are complementary if the sum of their measures is 90°. Find two complementary angles such that one of the angles is 142° less than 3 times the other angle.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #576867 by </B><A HREF=/tutors/aboutme.mpl?userid=Zucchini><B>Zucchini(70)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Zucchini><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=576867\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The two angles are 58 and 32. I got this by:\r<BR>\n" );
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document.write( "3x-142 + x =90 <BR>\n" );
document.write( "         4x=232<BR>\n" );
document.write( "           X= 58\r<BR>\n" );
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document.write( "Then, 3(58) - 142<BR>\n" );
document.write( "            174 - 142<BR>\n" );
document.write( "                    32 </SPAN>\n" );
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