document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=945630>Question 945630</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A line m goes through the point (4,-3) and is perpendicular to the line 3x+2y=9. The point (k,k+3) lies on this perpendicular line m. Find the value of k. Thanks for your help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #576849 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=576849\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A line m goes through the point (4,-3) and is perpendicular to the line 3x+2y=9. The point (k,k+3) lies on this perpendicular line m. Find the value of k. <BR>\n" );
document.write( "***<BR>\n" );
document.write( "3x+2y=9<BR>\n" );
document.write( "2y=-3x+9<BR>\n" );
document.write( "y=-3/2+9/2<BR>\n" );
document.write( "slope:-3/2<BR>\n" );
document.write( "slope of perpendicular line=2/3(negative reciprocal)<BR>\n" );
document.write( "using coordinates of given points  on the perpendicular line:<BR>\n" );
document.write( "slope=&#8710;y/&#8710;x=((k+3)-(-3))/(k-4)=2/3<BR>\n" );
document.write( "(k+6)/(k-4)=2/3<BR>\n" );
document.write( "3k+18=2k-8<BR>\n" );
document.write( "k=-26 </SPAN>\n" );
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