document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=945561>Question 945561</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The second side of a triangular deck is 5 feet longer than the shortest side and a third side that is 5 feet shorter than twice the length of the shortest side. If the perimeter of the deck is 64 feet, what are the lengths of the three sides? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #576794 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=576794\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let shortest side =S; second side =S+5 ft; third side=2S-5 ft<BR>\n" );
document.write( "Perimeter=sum of sides=64 ft<BR>\n" );
document.write( "64 ft=(S)+(S+5)+(2S-5)<BR>\n" );
document.write( "64 ft=4S Divide each side by 4<BR>\n" );
document.write( "16 ft=S ANSWER 1: The short side is 16 feet.<BR>\n" );
document.write( "second side=S+5=21 ft  ANSWER 2: The second side is 21 feet.<BR>\n" );
document.write( "third side=2S-5=32-5=27 feet ANSWER 3: The third side is 27 feet.<BR>\n" );
document.write( "CHECK<BR>\n" );
document.write( "Perimeter is 64 feet<BR>\n" );
document.write( "16 ft+21 ft+27 ft=64 ft<BR>\n" );
document.write( "64 ft=64 ft<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );