document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=945634>Question 945634</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For any integer \"n\", find i^(4n+a) when \"a\" takes on the following values.<BR>\n" );
document.write( "3 & 2\r<BR>\n" );
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document.write( "Please show all work-- I don't understand this type of problem </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #576793 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=576793\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hint: i^1 = i, i^2 = -1, i^3 = -i, i^4 = 1 and it repeats.\r<BR>\n" );
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document.write( "Also, i^(4n+a) = i^(4n)i^a = i^a\r<BR>\n" );
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document.write( "Now just plug in a = 2, 3. </SPAN>\n" );
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