document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=80399>Question 80399</A>: <I><SPAN STYLE=\"word-break: break-all;\"> translate and solve \r<BR>\n" );
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document.write( "when twice a number is subtracted from twenty-four, the result is six times the number. find the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #57677 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=57677\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You are looking for a number ... so let's call the missing number X.<BR>\n" );
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document.write( "When \"twice a number (or 2X) is subtracted from 24\" is a statement that translates to:<BR>\n" );
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document.write( "24 - 2X<BR>\n" );
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document.write( "The problem says that the result equals 6 times the number (or 6X)<BR>\n" );
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document.write( "Set this up as an equation:<BR>\n" );
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document.write( "24 - 2X = 6X<BR>\n" );
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document.write( "Solve this equation by first getting all the terms containing X on one side of the equal sign<BR>\n" );
document.write( "and all the plain numbers on the other side.  You can do this by adding 2X to the left<BR>\n" );
document.write( "side to cancel out the -2X.  But if you add 2X to the left side, you must also add 2X to the<BR>\n" );
document.write( "right side to keep the equation in balance.  Adding 2X to both sides results in:<BR>\n" );
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document.write( "24 - 2X + 2X = 6X + 2X<BR>\n" );
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document.write( "combining the -2X and +2X on the left side results in them canceling out and this<BR>\n" );
document.write( "makes the equation become just:<BR>\n" );
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document.write( "24 = 6X + 2X<BR>\n" );
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document.write( "Combining the 6X and +2X on the right side makes the equation:<BR>\n" );
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document.write( "24 = 8X<BR>\n" );
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document.write( "Solve by dividing both sides of this equation by 8 and you get:<BR>\n" );
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document.write( "24/8 = X<BR>\n" );
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document.write( "and after doing the division on the left side you get the answer of:<BR>\n" );
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document.write( "X = 3<BR>\n" );
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document.write( "as being the number you are trying to find.<BR>\n" );
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document.write( "Check ... from 24 subtract twice the number ... this is 24 - (2*3) = 24 - 6 = 18.  Does <BR>\n" );
document.write( "that equal 6 times the number or 6 times 3?   6 times 3 also equals 18. So the answer checks. <BR>\n" );
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document.write( "Hope this helps you to see how you just start breaking down a problem and converting<BR>\n" );
document.write( "the given information into algebraic terms. Then solve the equation that results from<BR>\n" );
document.write( "relating the algebraic terms to each other.<BR>\n" );
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document.write( " </SPAN>\n" );
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