document.write( "Question 945579: In 3 bowling games, Alice scores 139, 143 and 144. What score will Alice need in a fourth game in order to have an average score of 145 for all four games? \n" ); document.write( "
Algebra.Com's Answer #576765 by Horlaye(27)![]() ![]() You can put this solution on YOUR website! Let p represent the fourth score \n" ); document.write( " (add all scores/occurrence = average) \n" ); document.write( " (139+143+144+p)/4 = 145 \n" ); document.write( " (426+p)/4 = 145/1 \n" ); document.write( " Cross multiply \n" ); document.write( ". 426+p = 4(145) \n" ); document.write( " 426+p = 580 \n" ); document.write( " Collect like term \n" ); document.write( " p = 580-426 \n" ); document.write( " p = 154 \n" ); document.write( "Since p represent the fourth score \n" ); document.write( "Therefore Alice need to score 154 in her fourth game to get the average score of 145 \n" ); document.write( " |