document.write( "Question 945545: The length of a rectangular yard is 5 feet longer than its width, x. The area of the yard is 104 sq ft. Use a quadratic to solve for the width. \n" ); document.write( "
Algebra.Com's Answer #576750 by macston(5194)\"\" \"About 
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(X+5)(X)=104 sq ft
\n" ); document.write( "\"X%5E2%2B5X=104sqft\" Subtract 104 from each side
\n" ); document.write( "\"X%5E2%2B5X-104=0\"
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B5x%2B-104+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%285%29%5E2-4%2A1%2A-104=441\".
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\n" ); document.write( " Discriminant d=441 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-5%2B-sqrt%28+441+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%285%29%2Bsqrt%28+441+%29%29%2F2%5C1+=+8\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%285%29-sqrt%28+441+%29%29%2F2%5C1+=+-13\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B5x%2B-104\" can be factored:
\n" ); document.write( " \"1x%5E2%2B5x%2B-104+=+1%28x-8%29%2A%28x--13%29\"
\n" ); document.write( " Again, the answer is: 8, -13.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B5%2Ax%2B-104+%29\"

\n" ); document.write( "\n" ); document.write( "answers are 8,-13
\n" ); document.write( "ANSWER the width of the yard is 8 feet,
\n" ); document.write( "CHECK:
\n" ); document.write( "length = W+5=8+5=13 ft
\n" ); document.write( "Area=104 sq ft
\n" ); document.write( "104 sq ft=(13ft)(8ft)
\n" ); document.write( "104 sq ft=104 sq ft
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