document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=945510>Question 945510</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the measures of two supplementary angles is 180 degrees. If one angle measures 45 degrees less than twice the measure of its supplement, find the measure of each angle. (smallest first) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #576710 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=576710\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = one angle<BR>\n" );
document.write( "2x - 45 = other angle  {one angle is 45 less than twice its supplement}\r<BR>\n" );
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document.write( "x + 2x - 45 = 180   {supplementary angles add up to 180°}<BR>\n" );
document.write( "3x - 45 = 180  {combined like terms}<BR>\n" );
document.write( "3x = 225 {added 45 to each side}<BR>\n" );
document.write( "x = 75   {divided each side by 3}<BR>\n" );
document.write( "2x - 45 = 105 {substituted 75, in for x,into 2x - 45}\r<BR>\n" );
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document.write( "75° and 105° are the two supplementary angles<BR>\n" );
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