document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=945516>Question 945516</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Rachel, Stephanie and Tina begin running together on a 400 meter oval track.Rachel runs at a pace of 2 minutes per lap, Stephanie at a pace of 2 minutes 15 seconds per lap and Tina at a pace of 2 minutes 30 seconds per lap. How far has Rachel run when Stephanie first catches up to Tina? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #576707 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=576707\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Rachel, Stephanie and Tina begin running together on a 400 meter oval track.<BR>\n" );
document.write( " Rachel runs at a pace of 2 minutes per lap,<BR>\n" );
document.write( " Stephanie at a pace of 2 minutes 15 seconds per lap and <BR>\n" );
document.write( " Tina at a pace of 2 minutes 30 seconds per lap.<BR>\n" );
document.write( "How far has Rachel run when Stephanie first catches up to Tina?<BR>\n" );
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document.write( "Here is a better, more accurate way to do this problem, using meters/min<BR>\n" );
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document.write( "Change 2 min 15 sec to 2.25 min, and 2 min 30 sec to 2.5 min<BR>\n" );
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document.write( "Find their speeds in meter/min<BR>\n" );
document.write( "R = 400/2 = 200 m/min<BR>\n" );
document.write( "S = 400/2.25 = 177.8 m/min<BR>\n" );
document.write( "T = 400/2.5 = 160 m/min<BR>\n" );
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document.write( "When S catches up to (laps) T, she has run exactly 400 m further than T<BR>\n" );
document.write( "Let t = time for this to occur, write a distance equation; dist = speed * time<BR>\n" );
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document.write( "S's dist = T's dist + 400m<BR>\n" );
document.write( "177.8t = 160t + 400<BR>\n" );
document.write( "177.8t - 160t = 400<BR>\n" );
document.write( "17.8t = 400<BR>\n" );
document.write( "t = 400/17.8<BR>\n" );
document.write( "t = 22.5 min for S to catch up with T<BR>\n" );
document.write( "How far will R run in 22.5 sec at 200 m/min<BR>\n" );
document.write( "22.5 * 200 = 4500 meters<BR>\n" );
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