document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=945522>Question 945522</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Evaluate the functions when x = -2, 0, and 3<BR>\n" );
document.write( "1)f(x) = -0.75x - 1<BR>\n" );
document.write( "2)d(x) = -3/2x + 5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #576705 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=576705\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Evaluate the functions when x = -2, 0, and 3<BR>\n" );
document.write( "1)f(x) = -0.75x - 1<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "To find f(-2) sub -2 wherever there's an x<BR>\n" );
document.write( "f(-2) = -0.75*(-2) - 1<BR>\n" );
document.write( "f(-2) = 1.5 - 1<BR>\n" );
document.write( "f(-2) = 0.5<BR>\n" );
document.write( "=============<BR>\n" );
document.write( "Do the others the same way.<BR>\n" );
document.write( "--------------------------------------<BR>\n" );
document.write( "2)d(x) = -3/2x + 5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );