document.write( "Question 945376: A committee of 5 is to be chosen from 12 members of the Board of Directors, 3 of whom are accountants. How many ways can this done if at least two of the committee members must be accountant?
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Algebra.Com's Answer #576699 by Edwin McCravy(20055) $\"\"$ $\"About$

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A committee of 5 is to be chosen from 12 members of the Board of Directors, 3 of whom are accountants. How many ways can this done if at least two of the committee members must be accountant?
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document.write( "There are 3 accountants and 9 non-accountants.\r\n" );
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document.write( "Case 1. Choose 2 accountants, 3 non-accountants\r\n" );
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document.write( "Choose the 2 accountants 3C2 = 3 ways.\r\n" );
document.write( "Choose the 3 non-accountants 9C3 = 84\r\n" );
document.write( "That's 3*84 = 252 ways.\r\n" );
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document.write( "Case 1.  Choose all 3 accountants, 2 non-accountants\r\n" );
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document.write( "Choose all 3 accountants 3C3 = 1 way.\r\n" );
document.write( "Choose the 2 non-accountants 9C2 = 36\r\n" );
document.write( "That's 1*36 = 36 ways.\r\n" );
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document.write( "Grand total: 252+36 = 288\r\n" );
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document.write( "Edwin

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