document.write( "Question 945439: the ratio in the ages of A,B,C, six years before was 2:3:5 if the sum of their present ages is 168, find their ages \n" ); document.write( "

Algebra.Com's Answer #576691 by Fombitz(32388) $\"\"$ $\"About$

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1. $\"A%2BB%2BC=168\"$
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\n" ); document.write( " $\"%28A-6%29%2F%28B-6%29=2%2F3\"$
\n" ); document.write( " $\"3%28A-6%29=2%28B-6%29\"$
\n" ); document.write( " $\"3A-18=2B-12\"$
\n" ); document.write( "2. $\"3A-2B=6\"$
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\n" ); document.write( " $\"%28B-6%29%2F%28C-6%29=3%2F5\"$
\n" ); document.write( " $\"5%28B-6%29=3%28C-6%29\"$
\n" ); document.write( " $\"5B-30=3C-18\"$
\n" ); document.write( "3. $\"5B-3C=12\"$
\n" ); document.write( "From the eq. 1,
\n" ); document.write( " $\"C=168-A-B\"$
\n" ); document.write( "Substitute into eq. 3,
\n" ); document.write( " $\"5B-3%28168-A-B%29=12\"$
\n" ); document.write( " $\"5B-504%2B3A%2B3B=12\"$
\n" ); document.write( "4. $\"3A%2B8B=516\"$
\n" ); document.write( "Now subtract eq. 2 from eq. 4,
\n" ); document.write( " $\"3A%2B8B-3A%2B2B=516-6\"$
\n" ); document.write( " $\"10B=510\"$
\n" ); document.write( " $\"B=51\"$
\n" ); document.write( "Then,
\n" ); document.write( " $\"3A%2B8%2851%29=516\"$
\n" ); document.write( " $\"3A%2B408=516\"$
\n" ); document.write( " $\"3A=108\"$
\n" ); document.write( " $\"A=36\"$
\n" ); document.write( "and
\n" ); document.write( " $\"A%2BB%2BC=168\"$
\n" ); document.write( " $\"36%2B51%2BC=168\"$
\n" ); document.write( " $\"87%2BC=168\"$
\n" ); document.write( " $\"C=81\"$
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