document.write( "Question 945487: Solve the equation cotangent squared of the quantity of pi over 2 minus theta = secant of theta + 1 for for theta greater than or equal to 0 but less than 2 pi. \n" ); document.write( "
Algebra.Com's Answer #576690 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Solve the equation cotangent squared of the quantity of pi over 2 minus theta = secant of theta + 1 for for theta greater than or equal to 0 but less than 2 pi. \n" ); document.write( "*** \n" ); document.write( "use x for theta \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "lcd: cos^2(x) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "2cos^2(x)+cosx-1=0 \n" ); document.write( "(2cosx-1)(cosx+1)=0 \n" ); document.write( "cosx=1/2 \n" ); document.write( "x=π/3,5π/3 \n" ); document.write( "or \n" ); document.write( "cosx=-1 \n" ); document.write( "x=π \n" ); document.write( " \n" ); document.write( " |