document.write( "Question 80373This question is from textbook Algebra for college students
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document.write( ": I would like a solution to how it is done to evaluate each expression:
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document.write( "-2+ 1n e^3. I do know the answer is 1 (from the back of my text book's answers to the problem), but the log calculator on this web site had the answer as 0 because it was needed 0 divisions to get to 1. Please explain .
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Algebra.Com's Answer #57663 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! -2+ 1n e^3. \n" ); document.write( "------------- \n" ); document.write( "You have to know that lne^x = x \n" ); document.write( "Why? \n" ); document.write( "Well, ln means log(base e) \n" ); document.write( "So lne^3 means log(base e) e^3, and that log is 3 \n" ); document.write( "--- \n" ); document.write( "Wow, that was a mouthful. \n" ); document.write( "Anyway, for your problem: \n" ); document.write( "-2 + lne^3\r \n" ); document.write( "\n" ); document.write( "= -2 + 3 \r \n" ); document.write( "\n" ); document.write( "=1 \n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |