document.write( "Question 80373This question is from textbook Algebra for college students
\n" ); document.write( ": I would like a solution to how it is done to evaluate each expression:
\n" ); document.write( "-2+ 1n e^3. I do know the answer is 1 (from the back of my text book's answers to the problem), but the log calculator on this web site had the answer as 0 because it was needed 0 divisions to get to 1. Please explain .
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Algebra.Com's Answer #57663 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
-2+ 1n e^3.
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\n" ); document.write( "You have to know that lne^x = x
\n" ); document.write( "Why?
\n" ); document.write( "Well, ln means log(base e)
\n" ); document.write( "So lne^3 means log(base e) e^3, and that log is 3
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\n" ); document.write( "Wow, that was a mouthful.
\n" ); document.write( "Anyway, for your problem:
\n" ); document.write( "-2 + lne^3\r
\n" ); document.write( "\n" ); document.write( "= -2 + 3 \r
\n" ); document.write( "\n" ); document.write( "=1
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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