document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=80316>Question 80316</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help if you can,\r<BR>\n" );
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document.write( "Solve this system of equations\r<BR>\n" );
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document.write( "4a+7b=27\r<BR>\n" );
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document.write( "8a-3c=-22\r<BR>\n" );
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document.write( "6b-3c=24\r<BR>\n" );
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document.write( "The solution is [],[],[]  Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #57660 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=57660\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A) third equation minus second equation ... (6b-3c)-(8a-3c)=24-(-22) ... 6b-8a=46\r<BR>\n" );
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document.write( "B) two times second equation ... 2(4a+7b=27) ... 8a+14b=54\r<BR>\n" );
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document.write( "C) A+B ... (6b-8a)+(8a+14b)=46+54 ... 20b=100 ... b=5\r<BR>\n" );
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document.write( "from second equation ... 4a+(7*5)=27 ... 4a=-8 ... a=-2\r<BR>\n" );
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document.write( "from first equation ... (6*5)-3c=24 ... -3c=-6 ... c=2\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );