document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=945417>Question 945417</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the present age of father is equal to the sum of ages of his 5 children. 12 years hence, the sum of ages of his children will be twice the age of their father. find the percentage of the father. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #576581 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=576581\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> F=father's age S=sum of children's ages<BR>\n" );
document.write( "F=S<BR>\n" );
document.write( "2(F+12)=S+60 Substitute for S<BR>\n" );
document.write( "2(F+12)=F+60<BR>\n" );
document.write( "2F+24=F+60 Subtract 24 from each side<BR>\n" );
document.write( "2F=F+36 Subtract F from each side<BR>\n" );
document.write( "F=36 ANSWER: Father's current age is 36<BR>\n" );
document.write( "CHECK<BR>\n" );
document.write( "In 12 years, sum of children's age = twice fathers (Sum of children currently=father)<BR>\n" );
document.write( "S+60=2(F+12) Substitute for s<BR>\n" );
document.write( "F+60=2(F+12)<BR>\n" );
document.write( "36+60=2(36+12)<BR>\n" );
document.write( "96=2(48)<BR>\n" );
document.write( "96=96<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );