document.write( "Question 945410: you invested a total of $25000 at 3% and 4 1/2% simple interest. During one year, the two accounts earned $9000 . How much did you invest in each account? \n" ); document.write( "
Algebra.Com's Answer #576574 by vleith(2983)\"\" \"About 
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Let the amount you invest at 4.5% be x. Then the amount invested at 3% is \"25000-x\"\r
\n" ); document.write( "\n" ); document.write( "You are told
\n" ); document.write( "\"%28x%2A+0.045%29+%2B+%28%2825000-x%29%2A0.03%29+=+9000\"
\n" ); document.write( "Solve for x\r
\n" ); document.write( "\n" ); document.write( "\"0.045x+%2B+750+-+0.03x+=+9000\"
\n" ); document.write( "\"0.015x+=+8250\"
\n" ); document.write( "\"x+=+8250%2F%280.015%29\"\r
\n" ); document.write( "\n" ); document.write( "Solving for x gives a number greater than 25000. So the answer is \"you can't do that\".\r
\n" ); document.write( "\n" ); document.write( "To verify that, imagine you invested the entire 25000 at the higher rate of 4.5%. How much will that return in a simple interest year? $1125 which is nowhere near 9000.\r
\n" ); document.write( "\n" ); document.write( "Did you have a typo maybe?? Perhaps 900??\r
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